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Integral identity

  1. May 28, 2010 #1
    1. By considering each component of the vector A show that [tex]\iint A(u.n)ds = \iiint{(u.nambla)A+A(nambla.u)}dV[/tex] (A,u and n are vectors)



    2. Relevant equations



    3. Let A = ai + bj + ck. L.H.S: [tex] \iint ai (u.n)ds + \iint bj (u.n)ds +\iint ck (u.n)ds[/tex]
    R.H.S. = [tex] \iiint(u.nambla)ai dV+ \iiint(u.nambla)bj dV+ \iiint(u.nambla)ck dV + \iiinta(nambla.u)i dV ... [/tex]


    Sorry my latex is all over the place maybe just ignore this
     
  2. jcsd
  3. May 28, 2010 #2
    That gradient symbol is called "nabla." "nambla" is something else entirely.
     
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