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Integral in a terminal & more

  1. Aug 14, 2008 #1
    can anyone shed some light on this little monster?
     

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  3. Aug 14, 2008 #2

    Defennder

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    What you should do is to use the chain rule. Denote the upper limit of the integral (the limit which itself is an integral) as y(x). Then you should be able to see that dF/dx = dF/dy dy/dx.
     
  4. Aug 15, 2008 #3
    i'll take a look. ta
     
  5. Aug 16, 2008 #4

    HallsofIvy

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    The general Leibniz' formula is
    [tex]\frac{d}{dx}\int_{\alpha(x)}^{\beta(x)} F(x,t)dt= \frac{d\beta(x)}{dx}F(x,\beta(x))- \frac{d\alpha(x)}{dx}F(x,\alpha(x))+ \int_{\alpha(x)}^{\beta(x)}\frac{\partial F(x,t)}{\partial x} dt[/tex]
     
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