evaluate [tex]\int2(sec x)^3[/tex] with the limits as -pi/3 to 0 I tried all sorts of things from breaking it apart to substitution, but known of what I tried work. The book shows setting u=sec x & v=tan x Then it shows the first step as 2 (sec x tan x) - 2 [tex]\int(sec x) * (tan x)^2 dx[/tex] then evaluate both parts to -pi/3 to 0. Which is really what I'm not understanding. How did they integrate the first part & then still have the next part? I'm also not seeing how u & v come into play. Guess I'm just plain lost on this one.