As we know, [itex]\int \frac {1}{x} \, dx = ln (x) + C[/itex](adsbygoogle = window.adsbygoogle || []).push({});

But, what it would be, if [itex]x[/itex] is negative?

I calculated this way,

[itex]\int \frac {1}{x} \, dx = - \int \frac {1}{-x} \, dx = \int \frac {1}{-x} \, d(-x) = ln (-x) + C[/itex] [because, [itex]-x[/itex] has a positive value.]

**Physics Forums - The Fusion of Science and Community**

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Integral of 1 over x

Loading...

Similar Threads - Integral | Date |
---|---|

I Integrate a function over a closed circle-like contour around an arbitrary point on a torus | Yesterday at 12:51 PM |

A Integrate f(x) = tanh(c*x^b)? Wolfram says not possible ... | Mar 11, 2018 |

I Looking for additional material about limits and distributions | Feb 17, 2018 |

I Solving integral | Feb 9, 2018 |

I Derivative and Parameterisation of a Contour Integral | Feb 7, 2018 |

**Physics Forums - The Fusion of Science and Community**