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I try to take the integral of sqrt(4x-1) with respect to x...
The correct answer is sqrt((4x-1)^3)/6, but I always get
2sqrt((4x-1)^3)/3... Can someone explain how to solve that integral pls.
The correct answer is sqrt((4x-1)^3)/6, but I always get
2sqrt((4x-1)^3)/3... Can someone explain how to solve that integral pls.