- #1
Philosophaie
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I need to take the integral of an equation. I am trying to do Integration by Parts but I am coming up short.
I need to integrate (x^2 + y^2 + z^2)^(-3/2) dy for a Astronomy problem.
I tried:
u = x^2 + y^2 + z^2
du = 2*y dy
v=u^(-3/2)
dv = -3/2*u^(-5/2)
I can not do anything with the "y" in du.
Can you help?
I need to integrate (x^2 + y^2 + z^2)^(-3/2) dy for a Astronomy problem.
I tried:
u = x^2 + y^2 + z^2
du = 2*y dy
v=u^(-3/2)
dv = -3/2*u^(-5/2)
I can not do anything with the "y" in du.
Can you help?