Integral of dx/(sqrt(d^2+x^2))

  1. Hi there. Evaluating the expression [itex]\int\frac{dx}{\sqrt{x^{2}+y^{2}}}[/itex] I can get to the result [itex]ln(\frac{x+\sqrt{x^{2}+y^{2}}}{d})[/itex], but in my book it goes from this directly to [itex]ln (x+\sqrt{x^{2}+y^{2}})[/itex], a result wolframalpha says is valid for 'restricted [itex]x[/itex] values'. What does it mean? What are those restricted values? Why?

    Many thanks.
  2. jcsd

  3. Well, since this is indefinite integration both the results are correct as their difference is just the constant [itex]-\ln d[/itex].

    The question is: where did you get the constant [itex]d[/itex] from??

    The result is valid for any values of [itex]x,y, s.t. x^2+y^2\neq 0[/itex]

  4. Thank you. 'd' is actually a constant length (the distance from a point p to a disk, in an axis that goes through the center of the disk)
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