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hsostwal
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What is integral of tan(logx)? I couldn't find it on internet.
hsostwal said:What is integral of tan(logx)? I couldn't find it on internet.
Gregg said:Mathematica:
[itex]-i \left(\left(\frac{1}{5}-\frac{2 i}{5}\right) x^{1+2 i} \text{Hypergeometric2F1}\left[1-\frac{i}{2},1,2-\frac{i}{2},-x^{2 i}\right]-x \text{Hypergeometric2F1}\left[-\frac{i}{2},1,1-\frac{i}{2},-x^{2 i}\right]\right)[/itex]
CompuChip said:You might want to use FullSimplify (possibly with the additional assumption that x is real) and arrive at something with Euler B's, as I said.
The general formula for the integral of tan(logx) is ∫tan(logx)dx = ln|sec(logx)| + C, where C is a constant of integration.
To solve the integral of tan(logx), you can use the substitution method. Let u = logx, then du = 1/x dx. Substituting this into the integral, we get ∫tan(u)(1/x)dx. Using the trigonometric identity tan(u) = sin(u)/cos(u), we can rewrite the integral as ∫sin(u)/cos(u)(1/x)dx = ∫sin(u)/(x*cos(u))dx.
No, the integral of tan(logx) cannot be evaluated using integration by parts. This method is used for integrating products of functions, but in the case of tan(logx), we only have one function.
The limits of integration for the integral of tan(logx) depend on the problem at hand. Generally, the limits can be any real numbers that are within the domain of the function, which is (0,∞) for tan(logx).
Yes, there is a graph for the integral of tan(logx). It is a logarithmic function with an asymptote at x = 1. The graph starts at the origin and increases as x increases. The graph also has a point of inflection at x ≈ 2.081, where the function changes from concave up to concave down.