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**Integral of ....**

## Homework Statement

Hi, no directions were given it just says ∫(tan(x/2))^2 dx between 0 and pi.

You will get for the integral (1/2 (sin(2x)) - ((1/6)sin(2x))^3

I think that this is OK. Part of the graph of the origonal function dips below the axis so it end up being 0. I should change the limits of integral between [0,pi/2] then multiply that answer by 4 because there are 4 areas of that size.

Is this right?

So my final answer I got (4 (1/3)) so 4/3.

Thanks