1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Integral Problem

  1. Nov 12, 2006 #1
    The problem:

    Evaluate the integral
    [tex] \oint_{c} Fdr [/tex] for [tex] F = (2xy^4)i+(2x^2y^3)j [/tex] on the curve C consisting of the x-axis from x=0 to x=1, the parabola y=1-x^2 up to the y-axis, and the y-axis down to the origin

    Here is what I tried


    F(x,y)=[tex]<2xy^4,2x^2y^3> [/tex]


    [tex] \int\int_{D} =[(2x^2y^3)*\frac{\partial}{\partial x}-(2xy^4)\frac{\partial}{\partial y}] dA [/tex]


    = [tex] \int_{0}^{1} \int_{1-x^2}^{0} [4xy^3-8xy^3] dy dx [/tex]


    =1/10
     
    Last edited: Nov 12, 2006
  2. jcsd
  3. Nov 12, 2006 #2
    Ok I have redone this problem... multiple times... and now I am getting

    -1/10

    can someone confirm this for me, I am out of tries on my submission so I need to be sure when I submit this problem
     
  4. Nov 13, 2006 #3
    alright I solved it nevermind
     
  5. Nov 13, 2006 #4

    Office_Shredder

    User Avatar
    Staff Emeritus
    Science Advisor
    Gold Member

    I am so confused by the double integral
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Integral Problem
  1. Integration problem (Replies: 4)

  2. Integral Problem (Replies: 31)

  3. Integration problem (Replies: 9)

  4. Integration Problem (Replies: 7)

Loading...