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[tex]\int_0^{\pi}[f(x)+f''(x)]\sin xdx=2[/tex]. Given that [tex]f(\pi)=1[/tex], compute f(0).

I'm stuck on this, and I'm not sure where to start. The problem seems like a quickie, and the assumption that f'' is continuous seems curious. Do I have to use the FTC?

A hint, please??