Please forgive any formatting errors.

Is this correct?

[tex]\int x[/tex]

= [tex]\int e[/tex]

= [tex]\int e[/tex]

u = e

x = ln(u)

du = e

[tex]du/u[/tex] = dx

= ∫

a = ln(u)

EDIT: da = ln(u)

dv = 1/u du

v = ln(u)

= ln(u)

u = e

= ln(e

∫x

2∫x

∫x

**[tex]\int x[/tex]**^{ex}dx = ?Is this correct?

[tex]\int x[/tex]

^{ex}dx= [tex]\int e[/tex]

^{ln(x)ex}dx= [tex]\int e[/tex]

^{exln(x)}dxu = e

^{x}x = ln(u)

du = e

^{x}dx[tex]du/u[/tex] = dx

= ∫

__ln(u)__^{u}*(1/u)*dua = ln(u)

^{u}EDIT: da = ln(u)

^{u-1}**du**dv = 1/u du

v = ln(u)

= ln(u)

^{u+1}- ∫ [ln(u)]^{u}duu = e

^{x}= ln(e

^{x})^{ex+1}- ∫ [ln(e^{x})]^{ex}dx∫x

^{ex}dx = x^{ex+1}-∫x^{ex}dx2∫x

^{ex}dx = x^{ex+1}∫x

^{ex}dx = x^{ex+1}*(1/2)+C
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