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Integral problem

  1. Apr 13, 2009 #1
    suppose that f is continuous and (integral]0->2 f(x)dx = 6. Then (integral]0 -> pi/2 f(2sinb)cosbdb=?

    ok.... i'm totally lost here... how do u solve this without knowing what f(x) is..????
     
  2. jcsd
  3. Apr 13, 2009 #2

    dx

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    Do you know how to change variables in integrals? In the second integral, change variables to y = 2sinb.
     
  4. Apr 13, 2009 #3
    so if y = 2sinb then dy = 2cosbdb hence 1/2(integral]0->2f(y)dy) = 1/2(6) = 3
    Is this the answer?
     
  5. Apr 13, 2009 #4

    dx

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    Yes.
     
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