This is not homework I was wondering if I had to integrate(adsbygoogle = window.adsbygoogle || []).push({});

[itex] \frac{dx}{\sqrt{x^2-1}} [/itex]

Instead of doing the normal trig substitution what if I used

[itex] sin(u)^2-1=-cos(u)^2 [/itex] x=sin(u) dx=cos(u)du

But when I make the substitution I will get a negative sign under the radical, could I just pull it out as i and then some how extract the real part. How would I do it with the i in their.

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# Integral question with i.

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