Integral question

1. Apr 15, 2007

transgalactic

what is the integral of (tan x)^2

i added a file in wich i showed the way i tried to solve it

Attached Files:

• tan.GIF
File size:
295.1 KB
Views:
63
2. Apr 15, 2007

Mathgician

what is its identity?

3. Apr 15, 2007

transgalactic

the integral is:

(tan x)^2

4. Apr 15, 2007

Mathgician

I'm going to ask again, what is its direct trig identity

5. Apr 15, 2007

Mathgician

(tanx)^2=[(secx)^2]-1

Last edited: Apr 15, 2007
6. Apr 15, 2007

transgalactic

the trig identity is tangent

but my integral is
tangent square

7. Apr 15, 2007

Gib Z

Lol

Are you familiar with what Mathgician said? Its a well known Trigonometric Identity, $\tan^2 x = \sec^2 x -1$

Knowing that,

$$\int \tan^2 x dx = \int (\sec^2 x - 1) dx = \int \sec^2 x dx - \int 1 dx = (\int \sec^2 x dx ) - x$$

For the integral of (sec x) squared, if you don't already know it, try differentiating tan x, what is that?

8. Apr 15, 2007

Mathgician

If you are doing integrals right now, you have to have come across the derivative of tanx from differential calc class. No offense, but its the most basic derivative and identity is so common, I just thought you already should have known. I've seen you help many people on this board with integrals, I assumed that you would already knew or maybe you just had a brain fart or something. Its alright I have moments like these also.

Last edited: Apr 16, 2007
9. Apr 16, 2007

Gib Z

In fact, I just look through your attachment right there. You didn't even need Mathgicians or my suggestions for that identity, you got it yourself! 1/cos^2 x is sec^2 x :D You just needed to notice that was the derivative of tan x, instead of using cos^2 x = (1+cos 2x)/2

10. Apr 16, 2007

transgalactic

yeeepppp thank you very much

i got it
it was right under my nose