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Integral question

  1. Jan 8, 2008 #1
    the the integral of


    i devided the polinomials and got

    1+ (2/((x^3)-2))

    and afterwards i tried to split the deminator
    but i g0t realy complicated roots
    which are not alowing me to go further
    how do i continue after i devided the polinomials
  2. jcsd
  3. Jan 8, 2008 #2

    its 2 in the power of(1/3) not 2

    thats the big problem
    how do i dolve that
  4. Jan 8, 2008 #3
    If you want help, type it out w/o ambiguity or use LaTeX to avoid any confusion.
  5. Jan 8, 2008 #4
    if we solve ny the formula then we need to substitue eache 2
    with 2^(1/3)
  6. Jan 9, 2008 #5
    ye Difference of cubes
    but you wrote as if it was

    x^3 -8

    our question is:

    1+ (2/((x^3)-2))
    Last edited: Jan 9, 2008
  7. Jan 9, 2008 #6
    Well after looking at it and confirming with Mathematica, your numbers will be ugly. So you are probably on the right track, and I can't think of a slick way ... I tried several methods but didn't work out nicely at all.
  8. Jan 9, 2008 #7
    Lol, I just did it ... it is really ugly in the sense of too many fractions ... I don't even want to type it up. It's pretty ez though, just use Partial Fractions and you're done.
  9. Jan 9, 2008 #8
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