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Why is the anti derivative of 1/(x-3) equal to -ln[tex]\left|x+3\right|[/tex]. Why isn't it just ln[tex]\left|x-3\right|[/tex]. Does it have something to do with the absolute value? Thanks.
For [itex]x \neq 3[/itex]d/dx (log |x-3|) != 1/(x-3)
for x element of (-inf, inf) for sure!