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Integral Question

  1. Dec 5, 2008 #1
    Hi everyone,

    How to integrate the (4 - x^2)^1/2?

    Thank in advance
     
  2. jcsd
  3. Dec 5, 2008 #2
    Use a trigonometric substitution:

    [tex]
    \begin{gathered}
    \int {\sqrt {4 - x^2 } dx \Rightarrow } \left[ {\begin{array}{*{20}c}
    {x = 2\sin \theta } \\
    {dx = 2\cos \theta d\theta } \\

    \end{array} } \right] \hfill \\
    \int {2\cos \theta \sqrt {4(1 - \cos ^2 \theta )} } d\theta = 2\int 2 \sin \theta \cos \theta d\theta \cdot \cdot \cdot \hfill \\
    \end{gathered}
    [/tex]

    I think you can get it from there.
     
  4. Dec 5, 2008 #3

    Defennder

    User Avatar
    Homework Helper

    Wow, that's some Latex mastery you have there.
     
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