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Integral question

  1. Nov 14, 2004 #1
    [tex]
    \int \sqrt{tan(x)} dx
    [/tex]

    this problem has me stumped. any suggestions would be greatly appreciated. thanks
     
  2. jcsd
  3. Nov 14, 2004 #2
    I remember doing this a while back. It's pretty long-winded. Anyway, here's a push in the right direction:

    Use the substitution [itex]u=\sqrt{\tan(x)}[/itex], then:
    [tex]u^2=\tan(x)[/itex]
    [tex]2u\,du=\sec^2(x)\,dx[/tex]
    [tex]2u\,du=1+\tan^2(x)\,dx[/tex]
    [tex]dx = \frac{2u}{1+u^4}\,du[/tex]
     
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