$\int \frac{x-3}{x^2+2x-5}dx$

$x^2+2x-5=0$

$D=24$, so I can't get real root.

Curious3141
Homework Helper
$\int \frac{x-3}{x^2+2x-5}dx$

$x^2+2x-5=0$
$D=24$, so I can't get real root.
Hint: start off with completing the square on the denominator. In other words, express the denominator in the form $(x+a)^2 + c$ and go from there.