Integral task. How integrate?

  • Thread starter Tasy
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[itex]\int \frac{x-3}{x^2+2x-5}dx[/itex]

How integrate this task?

[itex]x^2+2x-5=0[/itex]

[itex]D=24[/itex], so I can't get real root.
 

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  • #2
Curious3141
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[itex]\int \frac{x-3}{x^2+2x-5}dx[/itex]

How integrate this task?

[itex]x^2+2x-5=0[/itex]

[itex]D=24[/itex], so I can't get real root.

OK, that line with the discriminant made no sense. The discriminant is greater than zero, so clearly the quadratic does have real, distinct roots.

Hint: start off with completing the square on the denominator. In other words, express the denominator in the form [itex](x+a)^2 + c[/itex] and go from there.
 
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