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Integral test

  1. May 22, 2008 #1
    1. The problem statement, all variables and given/known data

    The nth term for a sequence is the square root of [n/ (n^4 + 1)]
    Investigate whether it is convergence or divergence.

    2. Relevant equations

    Ratio test and integral test

    3. The attempt at a solution

    Ratio test will fail for this question, since no conclusion can be drawn if the ratio is 1. So I have to use integral test. I tried integrating the function using integration by part, bu that doesn't work. Trigonometric substitution fail as well. Any idea how to integrate the function?
  2. jcsd
  3. May 22, 2008 #2
    I'm assuming you want to find whether
    [tex]{\sum_n^\infty \frac{n}{n^4+1}}[/tex]

    Anyways, try doing a u-substitution with [tex]u=n^2[/tex].
  4. May 23, 2008 #3

    Gib Z

    User Avatar
    Homework Helper

    Harmony is actually looking for the limit of the sequence [tex]a_n = \sqrt{ \frac{n}{n^4+1}}[/tex].

    The reason foxjwill may have thought you wanted that series was because you spoke of the integral test, which is indeed a good idea - Prove the series converges, the nth term of the series must go to zero, and hence our sequence goes to zero. If you wished to take this route, as foxjwill said, u= n^2 is an easy substitution.

    However much easier than any method you have tried so far is the comparison test:

    [tex]a_n = \sqrt{ \frac{n}{n^4+1}} < \sqrt{ \frac{n}{n^4}}[/tex].

    That should do it.
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