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## Homework Statement

[tex]\int[/tex][tex]\frac{e^{z}}{1+e^{2z}}[/tex]

This is clearly a u substitution problem. My instinct is to let u = [tex]{1+e^{2z}[/tex]

so du = 2e^[tex]{2z}[/tex]dz

Now what? I don't see how this can be substituted into the original integral.

I could let u = e^z, but then that leaves e^2z. Clearly du in this case be e^zdz, but that also doesn't substitute in. e^2z = e^z * e^z. Could this be part of the solution? If somebody could provide some hint to get me going, I'd be grateful.