**[tex]\int[/tex][tex](X + 2)/\sqrt{3X-1}[/tex]**

one of my attempts: u=3X-1 , du/3=dX , x = (u+1)/3

1/3[tex]\int[/tex][tex](u+7).du/\sqrt{u}[/tex] = 1/3[tex]\int[/tex][tex]u .du/\sqrt{u}[/tex] + 7/3 [tex]\int[/tex][tex]du/\sqrt{u}[/tex] = 1/3[tex]\int[/tex][tex]u .du/\sqrt{u}[/tex] + 14/3. sqrt{u} = stuck...

the answer should be 2/27 . (3X + 20) .[tex]\sqrt{3X-1}[/tex]

one of my attempts: u=3X-1 , du/3=dX , x = (u+1)/3

1/3[tex]\int[/tex][tex](u+7).du/\sqrt{u}[/tex] = 1/3[tex]\int[/tex][tex]u .du/\sqrt{u}[/tex] + 7/3 [tex]\int[/tex][tex]du/\sqrt{u}[/tex] = 1/3[tex]\int[/tex][tex]u .du/\sqrt{u}[/tex] + 14/3. sqrt{u} = stuck...

the answer should be 2/27 . (3X + 20) .[tex]\sqrt{3X-1}[/tex]