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dnvu
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Please help me with this problem using the "integration by parts" method.
∫2x times natural log of (3 x) dx
Appriciate it!
∫2x times natural log of (3 x) dx
Appriciate it!
Integration by parts is a technique used in calculus to solve integrals of the form ∫u(x)v'(x)dx. It involves breaking down the integral into two parts, u(x) and v'(x), and using the product rule to find the integral.
To solve integrals by parts, you need to follow the formula ∫u(x)v'(x)dx = u(x)v(x) - ∫v(x)u'(x)dx. This means that you first choose u(x) and v'(x) based on the given integral, then solve for v(x) and u'(x) using the product rule. Finally, plug in the values into the formula to find the integral.
No, integration by parts is most useful for integrals that involve a product of functions, such as 2xln(3x). It may not work for other types of integrals, so it is important to understand when and how to use this technique.
The function 2xln(3x) is commonly used in integration by parts as it is a good example of a product of functions that requires this technique to solve. It helps to demonstrate the application of the formula and the product rule in finding integrals.
Sure, let's say we have the integral ∫2xln(3x)dx. To solve this, we first choose u(x) and v'(x). In this case, we can let u(x) = ln(3x) and v'(x) = 2x. Next, we find v(x) and u'(x) using the product rule: v(x) = x^2 and u'(x) = 2/x. Finally, we plug in the values into the formula to get ∫2xln(3x)dx = x^2ln(3x) - ∫x^2(2/x)dx = x^2ln(3x) - 2x + C, where C is the constant of integration.