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I am trying to solve this problem:

Find the right rieman sum and the integral (using the definition of integral) of:

(-x^2/3)-7 on the interval [0,4] using n subintervals.

So:

lim n->infinity of [sigma from i = 1 to n of (-(4i/n)^2/3)-7]*4/n

= lim n->infinity of [sigma from i = 1 to n of (-4i^2/3n^2)-7]*4/n

= lim n->infinity of [sigma from i = 1 to n of i^2 - 7]*(-16/4n^3)

= lim n->infinity of [sigma from i = 1 to n of i^2] - 7n*(-16/4n^3)

= lim n->infinity of ((n(n + 1)(2n + 1))/6)-7n*(-16/4n^3)

I don't how to go any farther with this...

Thanks for any help.

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# [Integrals] Just can't quite finish this

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