1. Sep 19, 2005 #1

   tmc

   

   I have this formula, and I just cant seem to be able to find any sensible answer:
   
   [tex]V^2_\textrm{rms}=\frac{1}{T}\int_{0}^{T}V^2_0sin^2(2ft\pi)dt [/tex]
   
   Depending on what I do, I either get an obviously wrong answer, 0, or [tex]V_0[/tex].

    

   Last edited: Sep 19, 2005

   tmc, Sep 19, 2005
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3. Sep 19, 2005 #2

   George Jones

   

   Staff Emeritus

   Science Advisor

   Gold Member

   The stuff under the integral sign needs to be squared. This is the S part of rms.
   
   Regards,
   George

    

   George Jones, Sep 19, 2005
4. Sep 19, 2005 #3

   tmc

   

   yeah, my bad. Edited it.
   Still dont get how to solve it though.

    

   tmc, Sep 19, 2005
5. Sep 19, 2005 #4

   George Jones

   

   Staff Emeritus

   Science Advisor

   Gold Member

   Use [itex]cos(2\theta) = 1 - 2sin^2 (\theta)[/itex] and [itex] f = 1/T[/itex].
   
   Regards,
   George

    

   George Jones, Sep 19, 2005

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