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Integrals, Physics

  • Thread starter tmc
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  • #1
tmc
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I have this formula, and I just cant seem to be able to find any sensible answer:

[tex]V^2_\textrm{rms}=\frac{1}{T}\int_{0}^{T}V^2_0sin^2(2ft\pi)dt [/tex]

Depending on what I do, I either get an obviously wrong answer, 0, or [tex]V_0[/tex].
 
Last edited:

Answers and Replies

  • #2
George Jones
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The stuff under the integral sign needs to be squared. This is the S part of rms.

Regards,
George
 
  • #3
tmc
289
1
yeah, my bad. Edited it.
Still dont get how to solve it though.
 
  • #4
George Jones
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Use [itex]cos(2\theta) = 1 - 2sin^2 (\theta)[/itex] and [itex] f = 1/T[/itex].

Regards,
George
 

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