1. Feb 15, 2006

### nick727kcin

how can i find this integral:

what would be u in this case? ugh im so confused

2. Feb 15, 2006

### finchie_88

$$u = 1+x^3$$
$$\therefore \frac{du}{dx} = 3x^2$$
Then integrate as usual.

by the way, is this pre-calculus?

3. Feb 23, 2006

### konartist

they teach us a little bit about integrals at the end of precalc.

4. Feb 23, 2006

### nick727kcin

thanks guys and this is calc 2. i just get confused with these integrals by parts and substition