1. The problem statement, all variables and given/known data Determine the function for which y '= x ^ 2, and (2,6) is a point of the graph. 2. Relevant equations y(x)=∫ x^2 dx 3. The attempt at a solution I tried doing this but didn't get the right answer y(x)=∫ x^2 dx = x^3/3 +c x=2 y=6 6=(2)^3 /3 +c C= 3,33... But according to the correctionpaper, its wrong . Answer should be x^3-3y+10 =0 How ??