INT x^(1/3) / x^(1/3) -1 dx(adsbygoogle = window.adsbygoogle || []).push({});

u = x^(1/3)

x = u^3

dx = 3u^2du

INT (u/u-1)3u^2du = 3

INT u^3/(u-1) du

INT [u^2 + u + 1/(u-1)]du

Then just integrate each part?

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Find the area of the region bounded.

y=2x - tan(0.3x), x-1, x=4, y=0

Need some guidance where to start here, and how the conditions will be used.

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# Integrals w/ natural logs

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