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Integrals w/ natural logs

  1. Jan 2, 2004 #1
    INT x^(1/3) / x^(1/3) -1 dx
    u = x^(1/3)
    x = u^3
    dx = 3u^2du

    INT (u/u-1)3u^2du = 3
    INT u^3/(u-1) du
    INT [u^2 + u + 1/(u-1)]du
    Then just integrate each part?

    Find the area of the region bounded.

    y=2x - tan(0.3x), x-1, x=4, y=0
    Need some guidance where to start here, and how the conditions will be used.
  2. jcsd
  3. Jan 3, 2004 #2


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    Looks reasonable to me!

    What guidance do you need for the second problem?

    Just integrate 2x- tan(0.3x) from 1 to 4.
  4. Jan 4, 2004 #3
    I don't see any ln in the integrand.
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