- #1

- 52

- 0

need to integrate 1/(1+e^x)

by using th rule 1/(ax+b) = (1/a)ln(ax+b)+c

i got (1/e^x)ln(1+e^x)+c

that is correct is it not?

because if i now differentiate that, i get 1/(1+e^x)..which is what we start with.

I am damn sure this is right, but its causing some arguments.

by using th rule 1/(ax+b) = (1/a)ln(ax+b)+c

i got (1/e^x)ln(1+e^x)+c

that is correct is it not?

because if i now differentiate that, i get 1/(1+e^x)..which is what we start with.

I am damn sure this is right, but its causing some arguments.

Last edited by a moderator: