Integrate 1/x2+a2.dx=1

1. Jan 18, 2007

king imran

integratio 1/x2+a2.dx=1
intervel0 to +infinity
find value of 'a'

2. Jan 18, 2007

king imran

Help Me Inthis Question

3. Jan 18, 2007

Hootenanny

Staff Emeritus
Hi there imran,

I'm guessing that your integrand, is something along the lines of;

$$\int^{\infty}_{0} \frac{1}{x^2} + a^2 \;dx = 1$$

Please note, that the rules of this forum prohibit us to provide help to someone who has not attempted there homework question before hand (assuming of course this is homework). Perhaps, if you posted your attempt, we could help you further...

4. Jan 18, 2007

mr_homm

The a^2 factor must be on the denominator, otherwise the integral is divergent both horizontally at infinity and vertically at zero.

Just clearing up the interpretation. Since the original poster has access to the original problem anyway, this doesn't constitute helping him. ;)

--Stuart Anderson

5. Jan 18, 2007

Gib Z

The Integral $$\int \frac{1}{x^2 + a^2} dx$$ looks very familiar to me :)

Maybe some trig will help you out?

6. Jan 19, 2007

Hootenanny

Staff Emeritus
You are quite correct of course!
And so it should
Good suggestion

7. Jan 19, 2007

king imran

find volume of solid y=x2-1 ,x=2 ,y=0 is relvived about y-asis

8. Jan 19, 2007

HallsofIvy

If this is a new problem, start a new thread.

Also, since it is obviously homework, post it in the homework thread and show what you have tried!

9. Mar 9, 2007

Padmashri

plz give me good sites to refer for integration,its applications

10. Mar 9, 2007

Krizalid

$$$\int {\frac{1} {{x^2 + a^2 }}dx} = \frac{1} {a}\tan ^{ - 1} \frac{x} {a} + c$$$

Just in case.

11. Mar 10, 2007

murshid_islam

does the following integral even exist?
$$\int^{\infty}_{0}\left(\frac{1}{x^2} + a^2\right) dx$$

12. Mar 10, 2007

cristo

Staff Emeritus
Look at the above post:

13. Mar 10, 2007

Gib Z

The question was actually with the a^2 also in the denominator, look at above posts. And that integral you stated only exists if a=0.

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