- #1

- 416

- 0

may i know how to integ [2x sin (x^2) dx]??the answer is -cos(x^2)

thanx.........

thanx.........

- Thread starter teng125
- Start date

- #1

- 416

- 0

may i know how to integ [2x sin (x^2) dx]??the answer is -cos(x^2)

thanx.........

thanx.........

- #2

- 91

- 0

use the subsititution u= x^2

- #3

- 3,763

- 9

[tex]\int 2xsin(x^2)dx = \int sin(x^2) dx^2 = -cos(x^2)[/tex]teng125 said:may i know how to integ [2x sin (x^2) dx]??the answer is -cos(x^2)

thanx.........

The clue is that

[tex]2xdx = dx^2[/tex]

marlon

edit : which is basically the same as what What has stated :)

- #4

- 416

- 0

oh.....okkk...thanx.......

- #5

- 75

- 0

Haha, you don't sound to sure on that. Does it make sense?teng125 said:oh.....okkk...thanx.......

- Last Post

- Replies
- 2

- Views
- 134K

- Last Post

- Replies
- 1

- Views
- 5K

- Last Post

- Replies
- 2

- Views
- 2K

- Last Post

- Replies
- 3

- Views
- 2K

- Last Post

- Replies
- 6

- Views
- 8K

- Last Post

- Replies
- 12

- Views
- 19K

- Replies
- 8

- Views
- 27K

- Last Post

- Replies
- 0

- Views
- 2K

- Last Post

- Replies
- 23

- Views
- 338K

- Last Post

- Replies
- 7

- Views
- 2K