Integrate [2x sin (x^2) dx]

  • Thread starter teng125
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  • #1
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may i know how to integ [2x sin (x^2) dx]??the answer is -cos(x^2)

thanx.........
 

Answers and Replies

  • #2
91
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use the subsititution u= x^2
 
  • #3
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teng125 said:
may i know how to integ [2x sin (x^2) dx]??the answer is -cos(x^2)
thanx.........
[tex]\int 2xsin(x^2)dx = \int sin(x^2) dx^2 = -cos(x^2)[/tex]

The clue is that

[tex]2xdx = dx^2[/tex]

marlon

edit : which is basically the same as what What has stated :)
 
  • #4
416
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oh.....okkk...thanx.......
 
  • #5
75
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teng125 said:
oh.....okkk...thanx.......
Haha, you don't sound to sure on that. Does it make sense?
 

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