may i know how to integ [2x sin (x^2) dx]??the answer is -cos(x^2)
use the subsititution u= x^2
[tex]\int 2xsin(x^2)dx = \int sin(x^2) dx^2 = -cos(x^2)[/tex]
The clue is that
[tex]2xdx = dx^2[/tex]
edit : which is basically the same as what What has stated :)
Haha, you don't sound to sure on that. Does it make sense?
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