[tex]\int[/tex] x/(2x+1) dx
The Attempt at a Solution
I tried factoring out the 2 on the bottom to get 1/2 [tex]\int[/tex] x/(x+1/2). then I put 1/2 [tex]\int[/tex] x+(1/2)-(1/2)/(x+1/2) dx.
from that i had, 1/2 [tex]\int[/tex]dx - 1/2[tex]\int[/tex]dx/(x+1/2)
finally x/2 - 1/4 ln lx+1/2l + C
My calculator keeps telling me it should be x/2 - 1/4 ln l2x+1l + C and every time try using a different trick i get a different answer. i'm sure i need to add 0, a-a, to get the answer but I can't figure out how to make it work.
If someone could please help me out it and show the steps as to where i went wrong it would be much appreciated. Been racking my brain over this seemingly simple problem. just can't seem to make it work.