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Integrate x^5sin(x^3)

  1. Jul 26, 2009 #1
    1. The problem statement, all variables and given/known data
    Integrate x^5sin(x^3). Using Integration by parts.


    3. The attempt at a solution

    I don't know which one to take du and u
    can anyone please help me out?

    Thanks a lot before hand!
     
  2. jcsd
  3. Jul 26, 2009 #2
    Well the expressions are pretty complicated and the exponents aren't exactly small if we only get to reduce them one at a time. To simplify a bit and to get familiar sin(u) term instead of the difficult sin(x^3) term try to do the substitution u= x^3 first. Once you have done this you should get an integral that is considerably easier to find using integration by parts.
     
  4. Jul 26, 2009 #3
    Remember the rule known as "LIATE" (aka: Logarithmic-Inverse Trigonometric-Algebraic-Trigonometric-Exponential) the one which comes first is your u and the one which appears later is your dv.

    In your question u=x5 because it is algebraic and dv=sin(x3) since it's trigonometric.
     
  5. Jul 27, 2009 #4
    Yea, but that doesn't help, because how will you integrate dv=sin(x3)? rasmhop's excellent advice is what rock_star should follow.

    I've never even heard of the "rule" LIATE, and to me, it is more confusing than just understanding how integration by parts works.
     
  6. Jul 27, 2009 #5
    I agree with you, I didn't notice that :redface: :redface:. I think the OP wanted to find a general rule for choosing u and dv when the integrand is a product of two functions from different categories in the list "LIATE" - in this case you will often be successful if you take the u to be the function whose category occurs earlier in the list and take dv to the rest of the integrand. The acronym LIATE helps one to remember the order but doesn't work in this case, I noticed that can't integrate sin(x^3).

    Anyway using rasmhop's substitution did you get: [tex]\frac{1}{3} sin(x^3) - \frac{1}{3} x^3 cos(x^3)[/tex] or is your answer different?
     
    Last edited: Jul 27, 2009
  7. Jul 27, 2009 #6
    Yes :smile: I solved the problem..
    I did it through U substitution...
    I took x^3 as U and then solved the problem. The got the above answer you mentioned :smile:
    and ILATE helped me with other problems of integration!
    Thank you so much!!! :D
     
  8. Jul 27, 2009 #7
    Thank you for all the help! :D I solved the problem!
    Ya.. I took du and u as u mentioned and it really helped! :D
    Thank you so much! :smile:
     
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