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Integrated rate law

  1. Jun 4, 2006 #1
    this seems a fairly straight forward qn but the ans at the back of the book does not agree with my ans :(

    we have a rate constant 5e-2 mol/L

    inital concentration of 1e-3 M

    calculate concentration after the time elapsed is 5e-3 s

    my ans is 7.5e-4 but the ans at the back claims it is 2.5e-4

    formula i using is the integrated rate law [A] = -kt + [A initial]

    did i miss something?
     
  2. jcsd
  3. Jun 4, 2006 #2

    siddharth

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    Gold Member

    The units of your rate constant aren't correct. It should be mole L-1 sec-1.
    Since it's a zero order reaction, your rate law is correct. Check your calculations.
     
  4. Jun 9, 2006 #3
    yea, thanks i manage to fig this one out :D
     
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