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Integrating (4x+1)^1/2

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  1. Aug 29, 2015 #1
    1. The problem statement, all variables and given/known data
    Integrate (4x+1)^1/2

    2. Relevant equations
    Integration (ax+b)^n dx= (ax+b)^(n+1)/ a(n+1)

    3. The attempt at a solution
    (4x+1)^(3/2)/ 4(3/2)
    = (4x+1)^(3/2)/6

    but the actual answer is
    3(4x+1)^(3/2)/8
     
  2. jcsd
  3. Aug 29, 2015 #2

    SammyS

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    Take the derivative of your result and the correct result. Compare to help you see where you went awry .
     
  4. Aug 29, 2015 #3

    Ray Vickson

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    No, the actual answer is what YOU obtained. Try differentiating your answer, to check if you get back your initial ##(4x+1)^{1/2}##.
     
  5. Aug 29, 2015 #4

    ehild

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    Your result is correct. (but do not forget adding a C constant :smile:)
     
  6. Aug 30, 2015 #5
    It does. Thank you!
     
  7. Aug 30, 2015 #6
    I keep forgetting to add the constant! Thanks!
     
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