Integrating a function

  • Thread starter blackbear
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  • #1
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Can someone help solve these two equations:

1. T[Cos(t)] = ∫[Sin(t-x)Cos(t)]dx the limits are from 0 to 2pi

2. T[Sin(t)]=∫[Sin(t-x)Sin(t)]dx; the limits are from 0 to 2pi


Thanks
 

Answers and Replies

  • #2
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What have you tried? You need to make a reasonable effort before we can provide any help.
 
  • #3
berkeman
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Can someone help solve these two equations:

1. T[Cos(t)] = ∫[Sin(t-x)Cos(t)]dx the limits are from 0 to 2pi

2. T[Sin(t)]=∫[Sin(t-x)Sin(t)]dx; the limits are from 0 to 2pi


Thanks

Per the PF rules, you need to show some effort at solving these problems before we can help you. But I'll offer a hint: If the integration is with respect to x (as indicated by the dx in each equation), then what can you do with the Sin(t) and Cos(t) terms in each equation?
 
  • #4
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Well Sin(t) and Cos(t) is a constant; each of these terms will come outside the integration, if we x is the integrating variable.
 
Last edited:
  • #5
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I computed both the integration and getting "0" for both results!!!
 
  • #6
berkeman
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I computed both the integration and getting "0" for both results!!!

Probably related to integrating sinusoidal functions from 0 to 2*PI, eh?
 
  • #7
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yes...the integrating result with 0 to pi gave me the "zero" results.
 
  • #8
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You really should post your attempted solution so that we can see what's plaguing you...
 
  • #9
berkeman
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yes...the integrating result with 0 to pi gave me the "zero" results.

No, you said 0 to 2*PI in your original post (OP) above.
 
  • #10
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my mistake..my result came to be "0" for both the equations when the limits are from 0 to 2pi.

regards
 

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