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Integrating a power of e

  1. Nov 14, 2009 #1
    1. The problem statement, all variables and given/known data

    Needing to integrate 3ye^3z dz

    2. Relevant equations



    3. The attempt at a solution
    I believe you use u substitution and u=3z du=3dz
    Then you get yze^3z. Is this correct?
     
  2. jcsd
  3. Nov 14, 2009 #2

    LCKurtz

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    If you differentiate yze3z with respect to z do you get what you started with? I don't think so, but can you fix it?
     
  4. Nov 14, 2009 #3
    >>Then you get yze^3z. Is this correct?
    No completely, you have an extra factor of z
     
  5. Nov 14, 2009 #4
    I believe differentiating ye^3z with respect to z will give 3ye^3z. Therefore, integrating 3ye^3z dz will be ye^3z. Correct?
     
  6. Nov 14, 2009 #5
    Yes.
     
  7. Nov 14, 2009 #6
    Sweet,thanks to the both of you
     
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