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Integrating exponential

  • Thread starter forty
  • Start date
  • #1
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(x^2).e^(-2a(x^2))

how would i integrate this? By parts?

If so using |udv = uv - |vdu (hope thats right)

would i let u = x^2 and dv = e^(-2a(x^2)) ?

but how do I integrate dv = e^(-2a(x^2)) to find v ?

any help appreciated :)
 

Answers and Replies

  • #2
33,152
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I think that integration by parts is the way to go, but there's more than one way to divide things up in this problem.

Try it this way:
u = x, dv = xe-2ax2dx

Now you have a dv that you have a hope of integrating (using an ordinary substitution).
 

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