- #1

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how would i integrate this? By parts?

If so using |udv = uv - |vdu (hope thats right)

would i let u = x^2 and dv = e^(-2a(x^2)) ?

but how do I integrate dv = e^(-2a(x^2)) to find v ?

any help appreciated :)

- Thread starter forty
- Start date

- #1

- 135

- 0

how would i integrate this? By parts?

If so using |udv = uv - |vdu (hope thats right)

would i let u = x^2 and dv = e^(-2a(x^2)) ?

but how do I integrate dv = e^(-2a(x^2)) to find v ?

any help appreciated :)

- #2

Mark44

Mentor

- 34,665

- 6,379

Try it this way:

u = x, dv = xe

Now you have a dv that you have a hope of integrating (using an ordinary substitution).

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