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Integrating exponential

  1. Apr 17, 2009 #1

    how would i integrate this? By parts?

    If so using |udv = uv - |vdu (hope thats right)

    would i let u = x^2 and dv = e^(-2a(x^2)) ?

    but how do I integrate dv = e^(-2a(x^2)) to find v ?

    any help appreciated :)
  2. jcsd
  3. Apr 18, 2009 #2


    Staff: Mentor

    I think that integration by parts is the way to go, but there's more than one way to divide things up in this problem.

    Try it this way:
    u = x, dv = xe-2ax2dx

    Now you have a dv that you have a hope of integrating (using an ordinary substitution).
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