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Integrating factor in Entropy (1/T)

  1. Sep 5, 2009 #1
    1. The problem statement, all variables and given/known data

    Show that the statment for Entropy [tex]dS = \int\frac{\delta Q}{T}[/tex] is path independent

    2. Relevant equations



    3. The attempt at a solution

    I am trying to show this by stating that dS is an exact differential by stating how [tex]\delta Q[/tex] is an inexact differential and by multiplying by integrating factor 1/T we now have an exact differntial with is path independent.

    I am trying to understand what it is that makes 1/T an integrating factor, or is this a poor way of doing it?


    Thanks
     
  2. jcsd
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