- #1

Naeem

- 194

- 0

I know how to prove it for "Mew" of x but how to do for "mew" of y

Maybe something like this.

Mdx (x.y) + Ndy ( x, y ) = 0

Assume this is differentiable so let us multiply by "mew" of x on both sides to make it exact.

Then M ( tilda ) the left term and N ( tilda ) equal to the right term

Then may be, Find partial with respect to x in the M terms. and partial with respect to y in the N terms. Is this idea/approach correct.

Thanks, for your help