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Integrating factor

  1. Mar 24, 2009 #1
    In the following problem how does -g end up becoming -g(m/g)?
    Isn't the derivative of -g just (-g^2/2)?
    http://users.on.net/~rohanlal/integfact.jpg [Broken]
     
    Last edited by a moderator: May 4, 2017
  2. jcsd
  3. Mar 24, 2009 #2
    I'm having trouble reading the scan, but from what I can tell, the factor of (m/c?) came from integrating the exponential, and g is constant with respect to the variable t. Then again, I don't have any context either.
     
  4. Mar 24, 2009 #3
    Yes, in this case g is a constant because you are integrating with respect to t. If you were integrating with respect to g (no clue why you would because I strongly suspect that this is the gravitational constant) then everything else would be a constant and you would get -g^2/2.
     
  5. Mar 25, 2009 #4
    Shouldn't I also have to find the integral of g, which would be gt?
     
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