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## Homework Statement

Solve 3xy^3 + (1+3x^2y^2)dy/dx=0 using integrating factors

## Homework Equations

y' + p(x) = q(x)

## The Attempt at a Solution

I'm having trouble putting the equation to y' + p(x) = q(x)

I distributed dy/dx so it becomes 3xy^3dy/dx + 1dy/dx+3x^2y^2dy/dx=0

But I didn't know where to go from there.

So I multiplied both sides by dx and 3xy^3dx + (1+3x^2y^2)dy=0

I don't know how to start this, please help!