Solve 3xy^3 + (1+3x^2y^2)dy/dx=0 using integrating factors
y' + p(x) = q(x)
The Attempt at a Solution
I'm having trouble putting the equation to y' + p(x) = q(x)
I distributed dy/dx so it becomes 3xy^3dy/dx + 1dy/dx+3x^2y^2dy/dx=0
But I didn't know where to go from there.
So I multiplied both sides by dx and 3xy^3dx + (1+3x^2y^2)dy=0
I don't know how to start this, please help!