[tex]y' (1+e^t) + e^ty = 0[/tex]
How do I get it in the form
[tex]y' +f(t)y = f(p) [/tex]
That is how do apply algebra to this so it is in the proper form to process it?
The Attempt at a Solution
Kind of hard to post my attempt. I can move the y' (1+e^2) to the right side then divide both sides by y' but that doesn't make it y' + something, rather y' x something.
I also tried moving everything to the right and canceling some stuff out but it doesnt seem to work.