Integrate -π∫π H(t-π/2)*sin(2t)dt
The Attempt at a Solution
I can rationalize the slightly simpler integral for the same limits of H(t)*sin(2t) as coming out to 0 due to the definition of the unit step function, but I'm wondering if the subtraction of π/2 changes it any. It's still integrating over the range of H(t), correct? So should it still work out to be 0?