Hi! I have a question about integrating a function with an infinite value. If you integrate a function with a place where the integrand diverges to infinity, I understand that the value of the integral should diverge to infinity. However, what happens when you set both bounds to be the value where the integral diverges? For example:(adsbygoogle = window.adsbygoogle || []).push({});

[tex]\int_{π/2}^{π/2} tan(x)\,dx[/tex]

In this example, tan(x), which diverges at π/2, is integrated from π/2 to π/2. I understand that normally, when you integrate with both bounds being the same, the result is zero because there is no length covered in the x direction. Is it the same in this case, or does integrating where the value of the integrand approaches infinity change this? It seems to me to resemble multiplying zero by infinity (where zero is the length and infinity is the height), which is undefined, but I don't know whether that is an adequate description of what is occurring for that to be the answer. Please let me know what you think. Thank you!

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# Integrating Infinities

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