Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Integrating over the phase in Mathematica

  1. May 16, 2012 #1
    Hi,

    I have a question about integrating over the phase of a function in Mathematica. The origins of this problem is in scale analysis.

    [itex] f(x,t)= \sum_n a_n \cos (n(kx-\omega t)) [/itex]

    for [itex] k,\omega \in \mathbb{R}[/itex]. I want to integrate an expression dependent on f over the phase

    [itex] \theta_n = n(kx-\omega t)[/itex] from [itex] [0,2\pi][/itex]. more specifically, I want to find

    [itex] \int_0^{2\pi} g(x,t) \ d \theta[/itex] where, for instance, [itex] g(x,t) = f_t + 1/2f_^2+ f^2 [/itex].



    Is there any automated way to do this without having to go back and manually change the phase to be a single symbolic variable?


    Thanks!

    Nick
     
  2. jcsd
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook

Can you offer guidance or do you also need help?
Draft saved Draft deleted