1. May 6, 2008 #1

   duki

   

   1. The problem statement, all variables and given/known data
   
   [tex]\int\sin(6\theta) d\theta[/tex]
   
   
   2. Relevant equations
   
   
   
   3. The attempt at a solution
   
   [tex]\int6\cos6\theta[/tex]
   
   Am I close?

    

   duki, May 6, 2008
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3. May 6, 2008 #2

   Feldoh

   

   If it helps do a u-sub where u=6theta
   
   Or you could think of it like this:
   
   If we take the derivative of [tex]\frac{d}{d \theta}(-cos(\theta)) = sin(\theta)[/tex]. That's sort of like the anti-derivative which you seek.
   
   If we take the derivative of [tex]\frac{d}{d \theta}(-cos(6 \theta)) = 6sin(6 \theta)[/tex].
   
   So from there it's easy to see that[tex]\int\sin(6\theta) d\theta = \frac{-cos(6\theta)}{6}[/tex]

    

   Feldoh, May 6, 2008
4. May 6, 2008 #3

   duki

   

   errr...
   
   [tex]\frac{-\cos6\theta}{6}[/tex]

    

   duki, May 6, 2008
5. May 6, 2008 #4

   duki

   

   thanks :)

    

   duki, May 6, 2008
6. May 6, 2008 #5

   Feldoh

   

   Yeah looks right^^

    

   Feldoh, May 6, 2008

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