- #1

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## Homework Statement

[tex]\int\sin(6\theta) d\theta[/tex]

## Homework Equations

## The Attempt at a Solution

[tex]\int6\cos6\theta[/tex]

Am I close?

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- Thread starter duki
- Start date

- #1

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[tex]\int\sin(6\theta) d\theta[/tex]

[tex]\int6\cos6\theta[/tex]

Am I close?

- #2

- 1,341

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Or you could think of it like this:

If we take the derivative of [tex]\frac{d}{d \theta}(-cos(\theta)) = sin(\theta)[/tex]. That's sort of like the anti-derivative which you seek.

If we take the derivative of [tex]\frac{d}{d \theta}(-cos(6 \theta)) = 6sin(6 \theta)[/tex].

So from there it's easy to see that[tex]\int\sin(6\theta) d\theta = \frac{-cos(6\theta)}{6}[/tex]

- #3

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errr...

[tex]\frac{-\cos6\theta}{6}[/tex]

[tex]\frac{-\cos6\theta}{6}[/tex]

- #4

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thanks :)

- #5

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Yeah looks right^^

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