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Integrating Sin

  • Thread starter duki
  • Start date
  • #1
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Homework Statement



[tex]\int\sin(6\theta) d\theta[/tex]


Homework Equations





The Attempt at a Solution



[tex]\int6\cos6\theta[/tex]

Am I close?
 

Answers and Replies

  • #2
1,341
3
If it helps do a u-sub where u=6theta

Or you could think of it like this:

If we take the derivative of [tex]\frac{d}{d \theta}(-cos(\theta)) = sin(\theta)[/tex]. That's sort of like the anti-derivative which you seek.

If we take the derivative of [tex]\frac{d}{d \theta}(-cos(6 \theta)) = 6sin(6 \theta)[/tex].

So from there it's easy to see that[tex]\int\sin(6\theta) d\theta = \frac{-cos(6\theta)}{6}[/tex]
 
  • #3
264
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errr...

[tex]\frac{-\cos6\theta}{6}[/tex]
 
  • #4
264
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thanks :)
 
  • #5
1,341
3
Yeah looks right^^
 

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