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## Main Question or Discussion Point

When doing integration such as [itex] \int_{0}^{2\pi} \hat{\rho} d\phi[/itex] which would give us [itex] 2\pi \hat{\rho} [/itex], must we decompose [itex] \hat{ρ} [/itex] into [itex] sin(\phi) \hat{i} + cos(\phi) \hat{j}[/itex] , then [itex] \int_{0}^{2\pi} (sin(\phi) \hat{i} + cos(\phi)\hat{j}) d\phi [/itex] , which would give us 0 instead?

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