1/(x2 +11x +29)
The Attempt at a Solution
I'm doing something wrong, but can't figure out what...
Complete the square so that the denominator equals (x+2)2+25
Then divide by 25: ((x+2)2)/25 + 1
Move that 25 into the squared part: ((x+2)/5)2+1
Substitute the squared part for u.
Find du/dx = 1/5, and therefore 5du=dx
Now we have 5*(integral sign) du / (u2+1)
This gives 5arctan(u)+C --> substitute u back for what you had before.
But the answer is 1/5arctan(u). Where did I go wrong?